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Study the paragraph and answer the question given below (Q1 & Q2):

Bhanu and Rosin sells TV, Lappy and Mouse. In January 2010, they earned 40% profit in Lappy and 25% profit on TV. Lappy contributes 35% towards their total sale in Rs. At same time total sale in rupee from Tv is 50% more than that of Lappy.

Q1. If Bhanu and Rosinhave earned 20% profit overall, then on Mouse they made

A.    15.2% profit B. 10.0% profit C. 10.0% loss D. 16.3% loss E. 23.4% loss

Q2. If Bhanu and Rosinmade 50% loss on Mouse, then overall they made
A.    12.3% profit B. 8.7% profit C. 0.4% loss D. 6.25% loss E. 20% loss

Q3. A man borrows Rs 6000 at 5% interest, on reducing balance, at the start of the year. If he repays Rs 1200 at the end of each year, find the amount of loan outstanding, in Rs, at the beginning of the third year.
A.    3162.75 B. 4125.00 C. 4155.00 D. 5100.00 E. 5355.00

Q4. A spherical metal of radius 10 cm is molten and made into 1000 smaller spheres of equal sizes. In this process the surface area of the metal is increased by:
A. 1000 times B. 100 times C. 10 times D. No change E. None of the above

Q5.The average of 7 consecutive numbers is P. If the next three numbers are also added, the averageshall
A.   remain unchanged B. increase by 1 C. increase by 1.5 D. increase by 2 E. None

Q6. If a trader makes a profit equal to the selling price of 75 articles when he sold 100 of the articles. What % profit did he make in the transaction?
(a)  33.33% (b) 75% (c) 300% (d) 150% (E) None

Q7. If he spends 1/3rd time of home work in Mathematics, then the number of hours he spends in rest of the subject in homework?
a)  1 (b) 2 (c) 3 (d) 4 (E) None

Q8. A reduction of 20% in price of sugar enables a person to purchase 6 kg more for Rs. 240. What is the original price per kg of sugar?
a)  Rs.10/kg (b) Rs. 8/kg (c) Rs. 6/kg (d) Rs. 5/kg (e) None

Q9. B is twice efficient as A and A can do a piece of work in 15 days. A started the work and after a few days B joined him. They completed the work in 11 days, from the starting. For how many days did they work together?
a)  1 day (b) 2 days (c) 6 days (d) 5 days (e) None

Q10. The speeds of the scooter, car and train are in the ratio of 1 : 4 : 16. If all of them cover equal distance the ratio of time taken/velocity for each of the vehicle is:
a)  256 : 16 : 1 (b) 1 : 4 : 16 (c) 16 : 4 : 1 (d) 16 : 1 : 4 (e) None

Solution:

1.Sol: E
Cost of Tv = 105/1.25 = 84 Rs.
Cost of Lappy = 70/1.4 = 50 Rs.
Total Profit = 20%
Total Cost = 200/1.2 = 500/3
Cost of Mouse = (500/3) – 84-50 = Rs. 98/3
Hence Loss on Mouse = [(98/3)-25] / (98/3) * 100 = 23.4

2. Sol: B
Referring to previous
Cost of Mouse = 25/0.50 = 50
Total cost = 84 + 50 + 50 = Rs.184
Total sale = Rs.200
Profit = (200 – 184)/184 * 100 = 8.7%

3. Sol: C
Amount at the end of the 1st year after repayment = 6000 × 1.05 – 1200 = Rs 5,100.
Therefore, amount at the beginning of the 2nd year will be Rs 5,100.
Amount at the end of the 2nd year after repayment = 5,100 × 1.05 – 1200 = Rs 4,155.
Therefore, amount at the beginning of the 3rd year will be Rs 4,155.

4. Sol: E
Let radius (in cm) of a smaller sphere be ‘r’.
Volume of the larger sphere = Total volume of 1000 smallerspheres
4/3 π(10)3 = r = 1 cm
Surface area of the larger sphere= 4π(10)2 = 400π cm2
Total surface area of 1000 smaller spheres
= 1000 × 4π(1)2 = 4000π cm2
Therefore, increase in the surface area of the metal= 4000 π – 400 π = 3600 π = 9 × 400 π cm2
Hence, surface area of the metal is increased by 9 times.

5.Sol: C
The average of 7 consecutive numbers will be the 4th number in the sequence.
Let the 4th number be x.
When the next 3 numbers are also added, the average will
be the mean of the 5th and the 6th of the sequence = (2x+3)/2 = x+1.5
Hence, the average shall increase by 1.5.

6. Sol: C
Let the cost price of each article be Re.1 and selling price of each article be Rs.x.
S.P. of 100 articles = C.P of 100 articles + Profit
=100x = 100 + 75x
=25x = 100 or x = 4
Profit = 4-1 /1 *100 = 300%

7. Sol: B
Total time spent in Mathematics home work
Time spent in home work / 3
= [45/360 * 24] / 3 = 1 Hr.
Time spent on remaining subject = 3-1 = 2hr

8. Sol: A
Due to 20% reduction in price, the person can save Rs.48 and hence can purchase 6 kg extra sugar. Therefore, new cost of sugar
48/6 = 8
As this new price is 20% less than the original price, original
price of sugar is
8/0.8 = 10

9. Sol: B

A         15       15       1

B          7.5                  2

11+2x = 15
2x = 4
X = 2.

10. Sol: A
d/y,    d/4y,    d/16y
1:1/(4*4):1/(16*16)
256:16:1

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