# Quantitative Aptitude Quiz for SBI / IBPS RRB 2018 Day 13

Q1.

**From a tank of petrol, which contains 500 litres of petrol initially, the seller sells 50litres of petrol each time and replenishes the tank with kerosene. Every time he sells out only 50litres of petrol. After replacing 4**^{th}time petrol with kerosene, find the total amount of kerosene in the mixture?A) 168.50litres

B) 185.54litres

C) 170.75litres

D) 171.95litres

E)None of these

Q2.

**A can contains a mixture of two liquids A and B in the ratio 9:7 when 8 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 9:8. How many litres of liquid A was contained by the can initially?**A)70.5litres

B)63litres

C)76.5litres

D)82.5llitres

E)None of these

Q3.

**A, B and C can alone complete a work in 10, 12 and 15 days respectively. A and C started the work and after working for 4 days, A left and B joined. In how many days the total work was completed?**A) 6 5/9 days

B) 6 2/9 days

C) 6 days

D) 5 4/9 days

E) 7 2/9 days

Q4.

**20 men can complete a work in 14 days and 20 women can complete the same work in 18 days. 8 men start the work and after working for 21 days, they are replaced by x women. If the remaining work is to be completed by x women in 9 days, then how many women should be employed?**A) 18

B) 24

C) 20

D) 16

E) 15

Q5.

**A Shopkeeper blends 2 varieties of tea, one CP is Rs.50 and another one CP is Rs.100 per kg. They were mixed in the ratio 7:2, if he sold the mixed variety at Rs.100/kg, how much was his profit percentage?**A)63.54%

B)63.63%

C)63.36%

D)66.36%

Q6.

**A slice from a circular pizza of diameter 14 inches is cut in a such a way that each slice of pizza has a central angle of 45°. What is the area of each slice of Pizza (in square inches)?**A) 16.25

B) 19.25

C) 18.25

D) 17.25

E) None of the Above

Q7.

**The area of a rectangle gets reduced by 9 square units, if its length is reduced by 5 units and breadth is increased by 3 units. If we increase the length by 3 units and breadth by 2 units, then the area is increased by 67 square units. Find the length and breadth of the rectangle.**A) 15m, 9m

B) 17m, 9m

C) 14m, 7m

D) 16m, 7m

E) None of the Above

Q8.

**A alone can complete a work in 5 days more than A+B together and B alone can complete a work in 45 days more than A+B together. Then in how many days A and B together can complete the work?**A) 16 days

B) 21 days

C) 15 days

D) 20 days

E) 25 days

Q9.

**Mr. Suresh has three daughters namely Ramya, Anita and Kiran. Ramya is the eldest daughter of Mr. Suresh while Kiran is the youngest one. The present ages of all three of them are square numbers. The sum of their ages after 5 years is 44. What is the age of Ramya after two years?**A) 15 years

B) 13 years

C) 18 years

D) 17 years

E) 16 years

Q10.

**The respective ratio between the present age of Monika and Deepak is 5: x. Monika is 9 years younger than Prem. Prem’s age after 9 years will be 33 years. The difference between Deepak’s and Monika’s age is same as the present age of Prem. What is the value of x?**A) 18

B) 10

C) 16

D) 11

E) 13

**Solution:**

**Q1. SOL: D**

^{4}

= 500[9/10]

^{4}= 500*6561/10000

= 328.05

Amount of kerosene = 500-328.05 = 171.95litres

**Q2. SOL: C**

Initial = 9x and 7x

Quantity of A in mixture left = (9x- (9/16)*8)

= 9x – (9/2)

Quantity of B in mixture left = (7x – (7/16)*8)

= 7x – (7/2)

[9x – (9/2)]/[7x – (7/2)+8] = 9/8

18x-9/14x + 9 = 9/8

144x-72 = 126x+81

18x=153

X = 153/18 = 8.5

9x = 9*8.5 = 76.5litre

Quantity of A in mixture left = (9x- (9/16)*8)

= 9x – (9/2)

Quantity of B in mixture left = (7x – (7/16)*8)

= 7x – (7/2)

[9x – (9/2)]/[7x – (7/2)+8] = 9/8

18x-9/14x + 9 = 9/8

144x-72 = 126x+81

18x=153

X = 153/18 = 8.5

9x = 9*8.5 = 76.5litre

**Q3. SOL: B**

Remaining work = 1 – 2/3 = 1/3

Now A left , B and C working

(B+C) = (1/12 + 1/15) = 9/60 = 3/20. They worked for x days and completed 1/3rd of work so (3/20)*x = 1/3, so x = 20/9 days

Total = 4 + 20/9

**Q4. SOL: D**

20 m in 14 days so 8 men in (20*14)/8 = 35 days

In 21 days 8 men complete (1/35)*21 = 3/5 work

Remaining work = 1 – 3/5 = 2/5

20 women do 1 work in 18 days so x women will do 2/5 work in 9 days

10*(2/5)*18 = x*1*9

In 21 days 8 men complete (1/35)*21 = 3/5 work

Remaining work = 1 – 3/5 = 2/5

20 women do 1 work in 18 days so x women will do 2/5 work in 9 days

10*(2/5)*18 = x*1*9

**Q5. SOL: B**

7*50 + 2*100 = 350+200 = 550

7+2 = 9

9*100 = 900

[900-550/550]*100 = 63.63%

7+2 = 9

9*100 = 900

[900-550/550]*100 = 63.63%

**Q6. SOL: B**

D = 14

R = D/2 = 14/2 =7

Area of each slice of Pizza =πr² * Θ/360°

= (22/7) * 7 * 7 * (45°/360°)

=19.25

R = D/2 = 14/2 =7

Area of each slice of Pizza =πr² * Θ/360°

= (22/7) * 7 * 7 * (45°/360°)

=19.25

**Q7. SOL: B**

Length = x; Breadth =y

xy – (x-5)(y+3) = 9

3x – 5y – 6 = 0 —(i)

(x+3)(y+2) – xy = 67

2x + 3y -61 = 0 —(ii)

solving (i) and (ii)

x = 17m ; y = 9m

xy – (x-5)(y+3) = 9

3x – 5y – 6 = 0 —(i)

(x+3)(y+2) – xy = 67

2x + 3y -61 = 0 —(ii)

solving (i) and (ii)

x = 17m ; y = 9m

**Q8. SOL: C**

Let (A+B) can do in x days, so

1/(x+5) + 1/(x+45) = 1/x

Solve, x

1/(x+5) + 1/(x+45) = 1/x

Solve, x

^{2}= 225, x = 15**Q9. SOL: C**

Square numbers – a, b, c

(a + 5) + (b + 5)+ (c + 5) = 44

a + b + c = 44 – 15 = 29

Possible values of a, b, c = 4, 9, 16 [Out of 1, 4, 9, 16, 25]

(a + 5) + (b + 5)+ (c + 5) = 44

a + b + c = 44 – 15 = 29

Possible values of a, b, c = 4, 9, 16 [Out of 1, 4, 9, 16, 25]

Ramya’s present age = 16; after two years = 18

**Q10. SOL: E**

Prem’s age after 9 years = 33 years

Prem’s present age = 33 – 9 = 24 years

Monika’s present age = 24 – 9 = 15 years

Deepak’s present age = 15 + 24 = 39 years

Ratio between Monika and Deepak = 15 : 39 = 5 : 13

X = 13

Prem’s present age = 33 – 9 = 24 years

Monika’s present age = 24 – 9 = 15 years

Deepak’s present age = 15 + 24 = 39 years

Ratio between Monika and Deepak = 15 : 39 = 5 : 13

X = 13

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